Devam Ediyor

CCTalk program needed. Source provided, needs more features

I'm looking for someone to modify C program.

The program opens Com port (defined in config file) and initialize cctalk device (bill validator), then listen and wait for note to be processed.

When note is processed it sends a request to IP (defined in config file).

All this function fine, with unencrypted cctalk and 16 bit crc.

Minor bugs: the program used to hang and it was fixed with small delay added for the commands sent to the device. This fix works on one PC with on Bill Validator and doesn't on different system with different bill validator :)

Encryption support - that's what has to be added, so the program can work with devices that don't support unencrypted cctalk.

In general that's all, I need the program more stable and to support encryption. At least for now that will be enough.

Beceriler: C# Programlama, C++ Programlama

Daha fazlasını görün: cctalk program, cctalk source, cctalk bill, cctalk bit crc, bill validator cctalk, program cctalk, source cctalk, cctalk encryption, small sharp function, program small, hang, cplusplus, cctalk, file source, delay fix, looking source, source file, program someone, minor bugs fix, small program encryption, programming encryption, program features, bill validator, cctalk bill validator, wait system

İşveren Hakkında:
( 1 değerlendirme ) Stara Zagora, Bulgaria

Proje NO: #744153

3 freelancer bu iş için ortalamada 273$ teklif veriyor

James1986

Hi sir, Please show me more details, and looking forward to work for you. Thanks, Aking

in 14 gün içinde500$ USD
(2 Değerlendirme)
4.2
TheArseneLupin

Hi, I read the requirements and I believe I can do that in 2 days and a half maximum. Would you please check PMB for more details.

in 4 gün içinde180$ USD
(12 Değerlendirme)
3.3
mtnkgr

We have done encryption for standalone games for various windows version in C# and ASP. Joomla interface for the web version of the game. C interface for gaming devices.

in 25 gün içinde140$ USD
(0 Değerlendirme)
0.0