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Oracle SQL Speedup

Here is the problem:

We represent a hierarchy of related record with a two column DB table called dataRecordRef. The columns are recordId and parentRecordId. A child record can have more than one parent record, so in this hierarchical representation there can be more than one path to the root for any given record.

We need a fast way given a set of record id's, what all it's descendant records are...namely a list of all the given records paths to the bottom of the tree. We have coded a solution as a single query that works, but we are unsatisfied with its performance.

We are fine if the solution is a single query like we coded, or if its a stored procedure.

We will pay more for more speedup over our current solution. In other words if you are 2x faster you can get more than if you are [url removed, login to view] faster. We would really like to see 10x performance as that is the performance we get with a MySQL stored procedure and we feel like we should be able to at least equal that on Oracle.

We include the following files:

* the dataRecordRef table as a CSV file you can import for testing

* the example query that we created that works but is too slow

* the input record ids as a csv that you will take as inputs to compute their ancestors against the provided dataRecordRef table

We will pay $100 for each doubling of performance up to 10x, which would be $1,000 award.

Beceriler: Veritabanı Geliştirme, Veritabanı Programlama, Oracle

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İşveren Hakkında:
( 0 değerlendirme ) Chennai, India

Proje NO: #6506813


Dear I'm Oracle Certified Professional, & very interested to do this task with 100% accuracy of your demand, and will be finish within very short time, because this task is very easy for me. Thanks and best regar Daha Fazla

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