Devam Ediyor

200 DoFollow Blogs perminent comments [POC:BS] Poll

Need: 200 DoFolllow Perminent Blog Comments

- Comments must be made within the next two weeks.

- Please send 20 initial comments so that we can do a quality check

- After 2 week comment period, a report of all blog links, their comments and the anchor text must be given

- Blog comments that are removed in the report, must be reposted (escrow will be released 1 week after comments are submitted to verify no comments are removed)

- Blog comments must be individually unique and no duplicate content

- 50%+ of blog comments must use our keyphrase as the anchor text

- All blog comments should come from domains with at least a PR1+

- No more than 3 links coming from the same IP address.

- This project has specific details which will be released after provider is accepted.

Beceriler: Link Oluşturma

Daha fazlasını görün: escrow domains, poll, poc project, dofollow, bs, initial poc, blogs need content, pr1 dofollow blogs, pr1 dofollow links, need dofollow blog comments, 200 building link, project reposted, comments blogs, dofollow blog pr1, blogs dofollow comments, need dofollow, quality dofollow links, dofollow pr1 blogs, 200 link, pr1 comments, blogs dofollow links, quality blog comments links, check blog comments, check blog comments link, keyphrase

İşveren Hakkında:
( 345 değerlendirme ) Boston, United States

Proje NO: #695790

Seçilen:

nish12nov

Many many thanks for another invitation. I am ready to start work. Thanks Nishant

15 gün içinde 100$ USD
(4 Değerlendirme)
3.4

5 freelancer bu iş için ortalamada 154$ teklif veriyor

kyo99

Please See PM!

in 16 gün içinde250$ USD
(16 Değerlendirme)
4.9
cncprashant

I want to work with you again. Thanks Prashant

in 10 gün içinde120$ USD
(1 Değerlendirme)
1.8
zymon

I 've good knowledge in blog commenting service, please reply me..

in 15 gün içinde150$ USD
(0 Değerlendirme)
0.0
kumar108nc

I will give you 100% do-follow blog with unique ip address.Thanks

in 10 gün içinde150$ USD
(0 Değerlendirme)
0.0