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Create a Time and Attendance System on MeanStack

Bu iş için 7 freelancer ortalamada $177 teklif veriyor

chunzuo

Dear Client. Nice to talk with you. I've read your job description. I'm a senior Web full-stack developer and working as an individual. ★I specialized in MEAN(MongoDB, Express, AngularJS, Node.js), MeteorJS Daha Fazla

$155 AUD in 3 gün içinde
(1 Yorum)
5.3
logos106

Hello, Nice to meet you. Interested and feeling confidence. Experienced in angular and node express JavaScript. Have done Angular project just before. Got good reviews from customers. 100% completed tasks. Pleas Daha Fazla

$155 AUD in 3 gün içinde
(8 Değerlendirme)
4.9
valiksoin

Hello How are you today? I am Valentin from Russia I am a senior Javascript engineer who has rich experience in NodeJS, React & Redux, GraphQl/Apollo, AngularJS. Having built great many node.js projects & react.js pro Daha Fazla

$200 AUD in 7 gün içinde
(11 Değerlendirme)
3.1
manish1986200821

Hello, I would love to work with your project in Mean Stack, I have 6+years of experience in Web Development with Angular 6, Express JS, Node JS and PHP. Need to discuss more on the project With Regards, Manis Daha Fazla

$170 AUD in 7 gün içinde
(3 Değerlendirme)
1.5
manvelesayan

Hello, I have been working in this field for 4 years, so I encountered any problem. I can guarantee that my work will surprise you. Some of my works are presented to your attention: 1. [login to view URL] 2. https:// Daha Fazla

$150 AUD in 10 gün içinde
(0 Değerlendirme)
0.0
bmachril

Hi. I have a large experience with mean stack developement. So I worked in various mean stack project small and medium. I will give you the best solution and hight code quality. Thanks.

$111 AUD in 10 gün içinde
(0 Değerlendirme)
0.0
RathodViral

Hello, I am skilled JavaScript developers who are well acquainted with advanced concepts of software engineering. I have a set of rules and practices that allow me to make the best use of the JavaScript framework and Daha Fazla

$300 AUD in 2 gün içinde
(0 Değerlendirme)
0.0