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494811 Quick and Easy - LAMP Project

I need a real simple program right now.

All it does is the following:

Check MySQL Database "Dbs1" for the table "tbl1" and verify that "field1" is NOT EQUAL TO "NULL" and for each entry where field1 is not equal to "NULL" copy that entry to Database "dbs2" (all table fields are copied to table in database "dbs2".

This is very, very, very simple. It just checks the variable of a field in one database->table and if matches (NOT EQUAL) it copies it to a second database->table.

So if in DB1 there is:

field1 field2 field3 field4

12 Hello 1019 Camero

It WOULD copy it so in DB2 we have an entry:

field1 field2 field3 field4

12 Hello 1019 Camero

If is:

field1 field2 field3 field4

NULL Hello 1019 Camero

it would not copy. That simple!

Beceriler: Her şey Kabul, MySQL, PHP

Daha fazlasını görün: lamp , easy database project, lamp database, variable mysql, variable entry project, mysql quick, quick copy, quick database project, php mysql quick, simple lamp project, easy simple project, lamp php mysql, php lamp project, lamp project, field variable php, easy quick project, db2 mysql, easy php project, php check variable, simple program project, php mysql entry table, php check mysql entry, project database copy

İşveren Hakkında:
( 3 değerlendirme ) Garden Grove, United States

Proje NO: #2240726

Seçilen:

theincredible

I can do it right now sir.

0 gün içinde 10$ USD
(104 Değerlendirme)
6.2